I am getting an error: line 5: conditional binary operator expected ; syntax error near `%' ; l-CodePudding

Here is my program code: I am getting an error which is: exam.sh: line 5: conditional binary operator expected exam.sh: line 5: syntax error near %' exam.sh: line 5: if [[ $i % 2 = 0 ]]'

#!/bin/bash
i=1;
for user in "$@" 
do
if [[ $i % 2 = 0 ]]
   then
   cd even
   mkdir $user
   .
   else if  [[ $i % 3 = 0 ]]
      then
      cd three
      mkdir $user
      .
      else 
        cd other 
        mkdir $user
   fi 
fi
i=$((i   1));
done

CodePudding user response：

[[ doesn't do arithmetics. You need (( for that.

if (( i % 2 == 0 ))

CodePudding user response：

Another option is to use $((...)) to generate a C-style "boolean" that you can test explicitly.

if [ "$(( x % 2 == 0 ))" = 1 ]; then
    echo "$x is even"
fi

This is objectively worse than if (( x % 2 == 0 )) in bash, but is useful if you need strict POSIX compliance.