I have written a program to pull a Maybe
out of a pair:
deMaybe :: (a, Maybe b) -> Maybe (a, b)
deMaybe (_, Nothing) = Nothing
deMaybe (x,Just y) = Just (x, y)
I know that Maybe
is a monad and (,) a
is a functor (among other typeclasses). I'm wondering if there is a higher-level function I'm missing, such as:
commute :: (Functor f, Monad m) => f (m a) -> m (f a)
My question is: can I write deMaybe
with a more general type signature like that of the hypothetical commute
, acknowledging that I am trying to commute one functor past another? Can this be done using functions such as fmap
, >>=
, pure
, &c.?
CodePudding user response:
You can work with sequence :: (Traversable t, Monad m) => t (m a) -> m (t a)
, but this requires a Traversable
. For t ~ (b, )
and m ~ Maybe
, this thus works as:
Prelude> sequence (2, Just 3)
Just (2,3)
Prelude> sequence (2, Nothing)
Nothing
A Traversable
is a typeclass for data structures that can be transformed to an item with the same shape. We need this to construct thus a 2-tuple (or list, or something similar).
or we can use sequenceA :: (Traversable t, Applicative f) => t (f a) -> f (t a)
as @chepner says, which is more general since all Monad
s are also Applicative
s:
Prelude> sequenceA (2, Just 3)
Just (2,3)
Prelude> sequenceA (2, Nothing)
Nothing