How to groupby by geometry column with Python?-CodePudding

I'm wondering whether someone can help me with this, may be naive, issue, please? Thanks in advance for your opinion. Q: How can I use groupby to group by ['id', 'geometry']? Assuming the geopandas data reads for: pts =

       id       prix  agent_code          geometry
  0    922769  3000 15  POINT (3681922.790 1859138.091)
  1   1539368  3200 26  POINT (3572492.838 1806124.643)
  2    922769  50   15  POINT (3681922.790 1859138.091)
  3   1539368  200  26  POINT (3572492.838 1806124.643)

I have used something like this:

 pts = pts.groupby(['id', 'geometry']).agg(prom_revenue=('prix',np.mean))..reset_index()

However Python raises the following error:

 TypeError: '<' not supported between instances of 'Point' and 'Point'

Thanks for your help, dudes!

CodePudding user response：

Use to_wkt from geometry column to convert shape as plain text:

out = pts.groupby(['id', pts['geometry'].to_wkt()], as_index=False) \
         .agg(prom_revenue=('prix', np.mean))
print(out)

# Output
        id  prom_revenue
0   922769        1525.0
1  1539368        1700.0

CodePudding user response：

If you take Corralien's answer a step further, you can restore the points again like this:

out = pts.groupby(['id', pts['geometry'].to_wkt()]).agg(prom_revenue=('prix', np.mean)).reset_index()
out.columns = ['id', 'geometry', 'pro_revenue']
out['geometry'] = gp.GeoSeries.from_wkt(out['geometry'])
out = gp.GeoDataFrame(out)
print(out)

Output:

        id                         geometry  pro_revenue
0   922769  POINT (3681922.790 1859138.091)       1525.0
1  1539368  POINT (3572492.838 1806124.643)       1700.0