Regex matchAll - get text between "*" without spaces-CodePudding

I wanna extract the text (without any spaces!) between two *. A sample:

That *is a* simple * demo*. This * will show * my problem.

So. I wanna have the text between the stars. But without any spaces. So if I use matchAll I wish to have the result of:

["is a", "demo", "will show"]

But my regex doesn't remove the empty spaces. Here it is:

var regex = /(\*\s{0,})(\s{0}[\w\s] \s{0})(\s{0,}\*)/ig;

In the end, the first spaces are removed correctly. But the end spaces are not ("will show " as an example).

Greetings, Florian

CodePudding user response：

You have to play with the greediness of quantifiers and target the last character with a character class that excludes spaces and asterisks:

/\*\s*([^*]*[^\s*])\s*\*/

Here [^*]* matches greedily all the content until the closing asterisk. [^\s*] forces the last character of the capture group to not be a space character and forces the backtracking (of the previous quantifier) until this one.

CodePudding user response：

let str = "That *is a* simple * demo*. This * will show * my problem.";

let arr = str.match(/\*[^*] \*/g).map(m => m.replace(/\*([^*] )\*/, "$1").trim());

console.log(arr);  // ["is a", "demo", "will show"]