How to find repetitions in lists?-CodePudding

How can I find repeating lists and the number of times they repeat?

For example:

#fsa and ghf are both lists
kol = []
for i in range(len(fsa)):
    if fsa[i] < ghf[i]:
        kol.append('1')
    else:
        kol.append('2')

    # this code puts my data into multiple lists in six intervals meaning six
    # elements of data per list
    start = 0
    end = len(fsa)
    for x in range(start,end,6):
        t = kol[x:x 6]
        l = (fsa[x:x   6])
        m = ghf[x:x   6]
        if m[0] < m[-1]:
            print(t)
        else:
            print(t)

Output:

['1', '1', '1', '1', '1', '1']
['2', '2', '2', '2', '2', '2']
['1', '1', '1', '1', '1', '1']
['1', '1', '1', '1', '1', '1']
['2', '2', '2', '2', '2', '2']

What I want to find out which lists repeat themselves and how many times each repetition occurs.

Example of what I want:

['1', '1', '1', '1', '1', '1'] 3  # the number of times it repeats
['2', '2', '2', '2', '2', '2'] 2

CodePudding user response：

You could use the collections.Counter dictionary subclass to find out what you want. To use it you will need to convert each list into a tuple to make it compatible (because the items being counted must be hashable).

from collections import Counter

lists = [['1', '1', '1', '1', '1', '1'],
         ['2', '2', '2', '2', '2', '2'],
         ['1', '1', '1', '1', '1', '1'],
         ['1', '1', '1', '1', '1', '1'],
         ['2', '2', '2', '2', '2', '2']]

counter = Counter(tuple(lst) for lst in lists)
for members, count in counter.items():
    print(list(members), count)

Output:

['1', '1', '1', '1', '1', '1'] 3
['2', '2', '2', '2', '2', '2'] 2