How to make a regex function in python?-CodePudding

I want regex that accepts any value in the format

int():str():int

For example, my input could be:- 0:apple4:2347

So, the input should accept a digit from 0-9 followed by a colon, then a string with an integer followed by a colon and a four-digit number. Please tell me how to do it?

CodePudding user response：

You could use this simple pattern:

(\d ):(\w ):(\d )

Explanation:

(\d ) match at least one digit or more
(\w ) match at least one word or more ([A-Za-z0-9_])

Example code:

import re

pattern = re.compile(r"(\d ):(\w ):(\d )")
text = "hello 0:apple4:2347 world 1234:banana39:4094"

matches = re.findall(pattern, text)
print(matches)

CodePudding user response：

Below is my answer

import re
testString=input("Enter String in format int():str():int");
regex=re.compile(r"^\d :\w :\d $")
if (bool(re.match(regex, testString))):
        print("String is :",testString)
else:
        print("String is not in format int():str():int")