If String(s) in List, output the index of List and which String(s) was found-CodePudding

py_list = ['Big apple pie','Small blueberry Pie','Cold Cherry Pie','Hot keylime pie']

keywords = ['blueberry','keylime']

for text in py_list:
    if any(xs in text for xs in keywords):
        itemlist = (py_list.index(text))
        print(xs,"was found in index: ", itemlist " of py_list")

Traceback (most recent call last): NameError: name 'xs' is not defined on line 7

How could I get output to be:

blueberry was found in index: 1 of py_list
keylime was found in index: 3 of py_list

CodePudding user response：

Firstly, you're misusing the any function. any() accepts an iterable and returns True when it finds that one of the items in the iterable is True or has a True boolean value.

Secondly, you'll need to declare the variable in the for loop at a higher hierarchy for it to reach the statements within the if statement, like so.

py_list = ['Big apple pie', 'Small blueberry Pie', 'Cold Cherry Pie', 'Hot keylime pie']

keywords = ['blueberry', 'keylime']

for text in py_list:
    for xs in keywords:
        if xs in text:
            itemlist = (py_list.index(text))
            print(xs, "was found in index: ", itemlist, " of py_list")

CodePudding user response：

The accepted answer can be improved by eliminating the need for a belated look-up of the index as follows:

py_list = ['Big apple pie','Small blueberry Pie','Cold Cherry Pie','Hot keylime pie']

keywords = ['blueberry','keylime']

for i, s in enumerate(py_list):
    for k in keywords:
        if k in s:
            print(f'{k} was found in index: {i} of py_list')

Output:

blueberry was found in index: 1 of py_list
keylime was found in index: 3 of py_list