Remove the part of string after the last occurrence in python-CodePudding

I have a string that has the path of the file stored in it.

path = \home\linux\testfile\abc\work

now I want to write a function with which I can remove all the characters occurring after the last '\\'. So,

new_path = \home\linux\testfile\abc

Is there a way I can do it? Slicing doesn't help because the number of characters after the last '\' isn't fixed. I know i need to post an attempt but i don't even understand how do i start this.

CodePudding user response：

You can use rsplit to start from the right and only split one time.

>>> path = '\home\linux\testfile\abc\work'
>>> path.rsplit('\\', 1)
['\\home\\linux\\testfile\\abc', 'work']

>>> path.rsplit('\\', 1)[0]
'\\home\\linux\\testfile\\abc'

CodePudding user response：

You can try with os library.

>>> os.path.split(r"\home\linux\testfile\abc\work")
('\\home\\linux\\testfile\\abc', 'work')

CodePudding user response：

Does it mean that I get the parent directory

>>> a="/home/pro"
>>> os.path.dirname(a)
'/home'

CodePudding user response：

You can use head, tail = os.path.split(path)

Check here