Trying to input a fraction and split it into a list but it causes problem when the numbers are more-CodePudding

fraction = list(input("Enter: "))
print(fraction)

When Inputting "99/100" I wanted it to print ["99", "/", "100"] not ['9', '9', '/', '1', '0', '0']

CodePudding user response：

You can use ".split" for this, for example:

thing1 = "abcdef"
thing1.split("c")

Gives the output:

['ab', 'def']

If you're bored and fancy fighting some spaghetti code for your own interest, it can be a fun challenge to code something equivalent to ".split()" yourself. Doing so gets you thinking about how Python works and trying to do it in the smallest big-O can introduce you to some interesting stuff about strings, arrays, and algorithm efficiency.

CodePudding user response：

If you want to keep the delimiter, as shown in the question, you can use the re module.

import re

fraction = input("Enter: ")
print(re.split("(/)", fraction))

CodePudding user response：

It should be used partition method and not split since with split will omit the separator parameter.

"99/100".partition('/')
#('99', '/', '100')

For nested fractions other strategies are recommended, re,...