Print a string which has the reverse order-CodePudding

I have the following question:
Print a string which has the reverse order 'Python love We. Science Data love We'

So I tried this:

strg = We love Data Science. We love Python
words = strg.split(" ") 
words.reverse()
new_strg = " ".join(words)
print(new_strg)

>>> Python love We Science. Data love We

But the answer isn't as expected because the . after Science is not at the proper place.

Is there a way to get the expected result?

CodePudding user response：

Can be done this way:

In [1]: s = "We love Data Science. We love Python"

In [2]: ". ".join(
    [" ".join(reversed(item.split())) for item in reversed(s.split("."))]
)
Out[2]: 'Python love We. Science Data love We'

CodePudding user response：

Examples:

Input :  "We love Python"
Output : "Python love We"  
Input :  "We love Data Science"
output : "Science Data love We"

reverse the words in the given string program

string = "We love Python"
s = string.split()[::-1]
l = []
for i in s:
    l.append(i)
print(" ".join(l))

or more simplest code:

string = "We love Python"
print(" ".join(string.split()[::-1]))

output:

Python love We

CodePudding user response：

Is this the output you need?

Python love We. Science Data love We

Then the code is

strg = 'We love Data Science. We love Python'
pos = len(strg) - strg.index('.') - 2
words = [e.strip('.') for e in strg.split()]
words.reverse()
new_strg = ' '.join(words)
print(new_strg[:pos]   '.'   new_strg[pos:])

Or another way to do it:

strg = 'We love Data Science. We love Python'
new_strg = [s.split()[::-1] for s in strg.split('.')][::-1]
print(' '.join(new_strg[0])   '. '   ' '.join(new_strg[1]))
#or
print('{}. {}'.format(' '.join(new_strg[0]), ' '.join(new_strg[1])))

Or to raise the bar:

strg = 'We love Data Science. We love Python'
print('. '.join([' '.join(new_strg.split()[::-1]) for new_strg in strg.split('.')[::-1]]))