https://www.jxzzdzw.com/asp.txt

Consult everybody, how the asp encryption above reduction? Thank you,

Bosses, bother to help restore

CodePudding user response:

The watch is a bit dizzy also nothing profound
It's not difficult to will slowly analysis of asp

CodePudding user response:

reference 1st floor tzlaoliu response:

the watch is a bit dizzy also nothing profound
Will slowly analysis is not difficult to asp

can help restore it for me?

CodePudding user response:

refer to the second floor weixin_43909329 response:

Quote: refer to 1st floor tzlaoliu response:

The watch is a bit dizzy also nothing profound
Will slowly analysis is not difficult to asp

can help restore it for me?

crack is not difficult, is a waste of time, everyone is so busy time, no one will be free for you to help restore

CodePudding user response:

There are such code, this is to belong to encrypt or confusion
'this code by the ASP code encryption tool 10 SP3 pro (Build 3200) create
'create time: 2017-02-28 21:57:30
'contact information: QQ: 30370740 MSN: [email protected]
'please do not modify any of the following code, in order to ensure the normal operation of the program

Dim OOOOO00 OOOOO0O, OOOOOO0, OOOOOOO, OOO00000
The Set OOOOOO0=Response: Set OOOOO0O=Request: Set OOO00000=Session: Set OOOOO00=Application: Set OOOOOOO=Server
If OOO00000 (OOO000OO (" 2==052 e2d) ")="" then
Dim OOO00O0O
On the Error Resume Next
Set OOO00O0O=OOOOOOO. Createobject (OOO000OO (" ps sq] ~ r ~ tr % x ~}}} "))
OOO00O0O. Open OOO000OO (" sq "" l") + OOOOOOO. Mappath (dbPathPart & amp; OOO000OO (" H @ CThe set OOO0OOO0=OOO00O0O. Execute (OOO000OO (" @ D6=64 E, E A, `, 52 e2 ` [52 e2a [52 e2b [52 the e2c [52 e2d [52 e2e [52 e2f [52 e2g [52 e2h, 7 c @ & gt;, H @ COOO00000 (OOO000OO (" 2==052 e2d "))=OOO0OOO0 (OOO000OO (" 52 e2 ` ")) & amp; OOO000OO (RSR) & amp; OOO0OOO0 (OOO000OO (" 52 e2a ")) & amp; OOO000OO (RSR) & amp; OOO0OOO0 (OOO000OO (" 52 e2b ")) & amp; OOO000OO (RSR) & amp; OOO0OOO0 (OOO000OO (" 52 ec2 ")) & amp; OOO000OO (RSR) & amp; 52 e2d OOO0OOO0 (OOO000OO (" ")) & amp; OOO000OO (RSR) & amp; 52 e2e OOO0OOO0 (OOO000OO (" ")) & amp; OOO000OO (RSR) & amp; OOO0OOO0 (OOO000OO (" 52 e2f)) & amp; OOO000OO (RSR) & amp; OOO0OOO0 (OOO000OO (" 52 e2g ")) & amp; OOO000OO (RSR) & amp; 52 e2h OOO0OOO0 (OOO000OO (" "))
OOO0OOO0. Close
The set OOO0OOO0=nothing
End the if

CodePudding user response:

Not reality, theory, actual cost is too high, it is better to buy the original