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Python regex: Explain why expression not matching

Time:08-14

I am using regex library to find words that are in between specific other words, for example, I want to match "world" if and only if a greeting precedes it and punctuation follows. To avoid matching word prefixes and suffixes, I added the additional condition [^a-zA-Z]. However, once I add these, regex cannot match the word anymore:

>>> import regex

>>> pat = regex.compile("(?<=[^a-zA-Z](hello|hi)\s )world(?=\s*[!?.][^a-zA-Z])")

>>> list(pat.finditer("hello world!"))
[]

>>> pat = regex.compile("(?<=\b(hello|hi)\s )world(?=\s*[!?.]\b)")

>>> list(pat.finditer("hello world!"))
[]

>>> pat = regex.compile("(?<=(hello|hi)\s )world(?=\s*[!?.])")

>>> list(pat.finditer("hello world!"))
[<regex.Match object; span=(6, 11), match='world'>]

How can this be explained? How to make sure to match whole words in the look ahead and behind sections?

CodePudding user response:

The reason is that when using (?<= and (?= there has to be present on the left and right what you specify.

Note that there is no word boundary after [!?.]\b when there is not a word character following any of the punctuation chars.

You could write the pattern as:

(?<=\b(?:hello|hi)\s )world(?=\s*[!?.](?!\S))

Explanation

  • (?<= Positive lookbehind, assert that to the left is
    • \b(?:hello|hi)\s Match either the word hello or hi and 1 whitespace chars
  • ) Close lookbhehind
  • world Match literally
  • (?= Positive lookahead, assert that to the right is
    • \s*[!?.] Match optional whitespace chars and one of ! ? .
    • (?!\S) Assert a whitespace boundary to the right
  • ) Close the lookahead

Or asserting a whitespace boundary to the left instead of the word boundary:

(?<=(?<!\S)(?:hello|hi)\s )world(?=\s*[!?.](?!\S))

Regex demo

CodePudding user response:

As correctly mentioned by @Michael, the width was the problem. The following does the trick:

>>> import regex

>>> pat = regex.compile("(?<=([^a-zA-Z]|^)(hello|hi)\s )world(?=\s*[!?.]($|[^a-zA-Z]))")

>>> list(pat.finditer("hello world!"))
[<regex.Match object; span=(6, 11), match='world'>]

>>> list(pat.finditer("hello world!x"))
[]

>>> list(pat.finditer("xhello world!"))
[]
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