Initialise a list element referring to an earlier element from the same list-CodePudding

Given the list

l = [ "ALPHA ONE", 123, _( "Alpha One" ), _( "ALPHA ONE" ) ]

where elements 2 and 3 (the translated text) are both tied directly to element 0.

Is it possible to define the list in which elements 2 and 3 dynamically refer to element 0? Is there a notation/mechanism for a list element to be initialised by referring to an earlier element?

For example, something along the lines of

l = [ "ALPHA ONE", 123, _( [ 0 ].title() ), _( [ 0 ].upper() ) ]

This would make life easier/safer as I don't want to have to define essentially the text over and over.

CodePudding user response：

From Python 3.8 this is possible using assignment expressions (the walrus operator). Assign the first element to a name using the walrus operator and then reuse this variable in the other elements

l = [(x := "ALPHA ONE"), 123, _(x.title()), _(x.upper())]

CodePudding user response：

Is there a reason you need to put it in a list literal? Also, this seems more like a tuple.

t = "ALPHA ONE"
l = (t, 123, _(t.title()), _(t.upper()))