I am using Stripe to integrate payments in my e-commerce website and Django as a web framework and I would like to create a custom administration site to manage the store, therefore I want to create a Command model whenever a stripe session has been paid.

from .models import Command # I have a Command model

class CommandView(views.APIView):
    def post(self, request, format=None):
        try:
            checkout_session = stripe.checkout.Session.create(
                line_items=[
                    {
                        'price': 'some price id',
                        'quantity': 1,
                    },
                ],
                mode='payment',
                success_url='http://localhost:3000/success/{CHECKOUT_SESSION_ID}',
                cancel_url='http://localhost:3000/store',
                billing_address_collection='auto',
            )
            if checkout_session['payment_status'] == 'paid':
                # this will never work because the status in this view is always unpaid
            return Response({'url': checkout_session['url']})
        except Exception as e:
            return Response({'error': e})

The solution I found is to execute the code in the success_url view but I'm wondering if it's possible to pay and to avoid getting into this url like immediately closing the tab... And maybe my solution of creating a Command model to see details of a command in the administration like color of product... is wrong, can you give some advices.

CodePudding user response：

You could try using Ajax to call your view function and handle it using JQuery / Javascript.

This stackoverflow question may be able to help you further.

CodePudding user response：

The recommended way to achieve this is through webhooks. This guide on fulfilling orders is a good example.