C - While loops once extra after checking condition?-CodePudding

I am trying to figure out the following code:

#include <stdio.h>
#define TEN 10
int main(void)
{
    int n = 0;
    
    while (n   < TEN)
        printf("]", n);
    return 0;
}

This prints 1 through 10. Isn't it supposed to print 1 to 9 only, since n will make it 10, and the condition while (10 < TEN) would fail hence should exit before printing?

When I change it to while ( n < TEN) I get 1 to 9, which makes sense because the addition is made before the check.

My so far understanding is that the n will add after the condition has been checked, hence it will print 10 (since n checks before, and n check after). Is that correct?

Thanks!

CodePudding user response：

With n (postfix increment operator), the value of n gets incremented after the while statement, therefore the while condition n < TEN is first verified, and only after the value of n is updated.

When the last iteration of your while instruction while (n < TEN) is executed, n is still 9 (and gets incremented by 1 right after) that's why it prints 10 as the last value:

    1    2    3    4    5    6    7    8    9   10