Is there a way to compare dates and store them in an array?-CodePudding

I'm currently working on a website where Objects are sorted. The Objects are from a database where it's stored with a date (2022-10-13 02:07:11). Is there a way to compare dates and store the ones that are created on the same date? For example: If there are two objects that were created on 2022-10-13, but with at a different time, I would like to save these in an array with the name of the date. I can't change how it's saved because it's not my DB.

I hope you understand how I mean it.

CodePudding user response：

(I don't know how you want it or how your database is exactly so you might have to change some things)

Try using (something like) this:

let sorted = {};
// replace "data" below with your key
for(key in data){
    if(!sorted[data[key].date]){
        sorted[data[key].date] = [];
    }

    sorted[data[key].date].push({key: data[key]});
}

Example in my case:

let data = {
  "a": {
    "date": "2022-10-13 02:07:11"
  },
  "b": {
    "date": "2022-10-13 00:00:00"
  },
  "c": {
    "date": "2022-10-10 02:07:11"
  }
};

let sorted = {};

for (key in data) {
  if (!sorted[data[key].date]) {
    sorted[data[key].date] = [];
  }

  sorted[data[key].date].push({
    key: data[key]
  });
}

console.log(sorted);

CodePudding user response：

A reduce is useful here

Give us more details of the object to give a more tailored answer

const obj = [
{ "id": "a1", "date": "2022-10-13 01:07:11" },
{ "id": "a2", "date": "2022-10-13 02:07:11" },
{ "id": "a3", "date": "2022-10-13 03:07:11" },
{ "id": "b",  "date": "2022-10-14 02:07:11" },
{ "id": "c1", "date": "2022-10-15 01:07:11" },
{ "id": "c2", "date": "2022-10-15 02:07:11" },
{ "id": "c3", "date": "2022-10-15 03:07:11" },
{ "id": "d",  "date": "2022-10-16 01:07:11" }
];
const grouped = obj.reduce((acc,cur) => {
  const key = cur.date.split(" ")[0];
  (acc[key] = acc[key] || []).push(cur);
  return acc;
},{})
console.log(grouped);