How can I get the different elements in the two arrays-CodePudding

const character = [
  { id: 1, na: "A" },
  { id: 2, na: "B" },
  { id: 3, na: "C" },
  { id: 4, na: "D" },
  { id: 5, na: "f" },
];

const character2 = [
  { id: 3, na: "C" },
  { id: 4, na: "D" },
];

How can I get the different elements in the two arrays For example, I need items A ,B AND F

CodePudding user response：

From the way you worded your question, it looks as if you're looking for a way to find all the elements in an array "A" that do not intersect with an array "B"

If that's the case, you can use array.includes

const a = [
    1,2,3
]

const b = [
    3
]

const filtered = a.filter(x => !b.includes(x))
console.log(filtered);

CodePudding user response：

Another way would be to create a new Set() first and compare against its content:

const arr = [
  { id: 1, na: "A" },
  { id: 2, na: "B" },
  { id: 3, na: "C" },
  { id: 4, na: "D" },
  { id: 5, na: "F" }],
  exc = [
  { id: 3, na: "C" },
  { na: "D", id: 4 }]; // the comparison will work, regardless of the property order

// create an "exclusion object" EXO (an ES6 Set):
const exo = exc.reduce((a,{id,na})=>a.add(`${id}:${na}`), new Set());

// filter by checking against an existing set member of EXO:
const res = arr.filter(({id,na})=>!exo.has(`${id}:${na}`));

console.log(res)

This approach compares for a static set of properties, but it can easily be set up to look for varying properties too.