Detect if string is a quote-CodePudding

I want to detect when a string is a quote of some kind. For my use case a string can be classed as a quote if it starts with a quotation mark, which will enable me to mark the string as a quote whilst it is being typed out.

Test cases

✅ "I am a quote
✅ 'I am a quote
✅ “I am a quote
✅ “I am a quote
❌ I am not a quote
❌ This isn't a quote

CodePudding user response：

My solution here is quite simple and checks for strings starting with “"':

const getInputTextType = (inputText: string) =>
  /^[“"']/.test(inputText.trim()) ? "quote" : "text";

console.log(getInputTextType('"I am a quote"'));
console.log(getInputTextType("'I am a quote"));
console.log(getInputTextType("“I am a quote"));
console.log(getInputTextType("  “I am a quote  "));
console.log(getInputTextType("I am not a quote"));
console.log(getInputTextType("This isn't a quote"));

If anyone knows of any instances where a potential quote wouldn't be caught (based on starting with a quotation mark) let me know.

CodePudding user response：

If the only thing to check is the first character, then just compare that first character with includes against the string of possible quote characters:

const getInputTextType = (inputText) =>
  `“"'`.includes(inputText.trim()[0]) ? "quote" : "text";

console.log(getInputTextType('"I am a quote"'));
console.log(getInputTextType("'I am a quote"));
console.log(getInputTextType("“I am a quote"));
console.log(getInputTextType("  “I am a quote  "));
console.log(getInputTextType("I am not a quote"));
console.log(getInputTextType("This isn't a quote"));