Read string date in bash with year and month only-CodePudding

Is there a straightforward way to parse date in Bash with year and month only, eg in format YYYY-mm?

This does not work:

$ date -d "2022-12"  "%Y-%m"
date: invalid date ‘2022-12’

In Python, this works:

>>> from datetime import datetime
>>> datetime.strptime("2022-12", "%Y-%m")
datetime.datetime(2022, 12, 1, 0, 0)

CodePudding user response：

Correct command is (at least it works for me MacOS):

date -jf "%Y-%m" "2022-12"
>Wed Dec 21 12:45:05 IST 2022

In your case date is incorrect since you doin't have day. The solution is simply add '01' day to source date:

my_date='2022-12'
date --date="${my_date}-01"
>Thu Dec  1 00:00:00 UTC 2022

CodePudding user response：

Create a function with a default daynumber (possible in .bashrc)

ymdate() {
  date -d "$1-1"  "%Y-%m-%d"
}

Next call the function like

ymdate 2022-12