Is it possible, and how should regex look like to get everything after the closing bracket or get everything if there are no brackets at all?

example:

possible input 1:

[12,45] some text

possible input 2: some text

expected to get:

 some text

I found something like lookbehing conditional, and tried:

(?(?<=\])((?<=\])(.*))|(.*))

but didn't work.

This works for the input with brackets:

(?<=\])(.*)

And this works for input without brackets:

(.*)

but is it possible to get one expression to match both input cases?

CodePudding user response：

This regex, you need OR aka |:

(?<=]\s|^)[\w\s] 
#      ^ 
#      |
#    there

The regular expression matches as follows:

Node	Explanation
(?<=	look behind to see if there is:
]	]
\s	whitespace (\n, \r, \t, \f, and " ")
|	OR
^	the beginning of the string
)	end of look-behind
[\w\s]	any character of: word characters (a-z, A- Z, 0-9, _), whitespace (\n, \r, \t, \f, and " ") (1 or more times (matching the most amount possible))

Online Demo

regex101

CodePudding user response：

In python you can use the sub command from the re package:

Code:

import re

text = "[12,45] some text\nsome text"
output = re.sub(r'\[.*?\]\s?', '', text)
print(output)

Output:

some text
some text

Regex to remove the contents within and including the square brackets.

• \[.*?\]\s?

• \[ = left square bracket

• .*? = zero or more characters (optional)

• \] = right square bracket

• \s? = space (optional)