I'm trying to manipulate this object so it matches the corresponding count to its id.
const data= [
[
{id: "333", count: 555},
{id: "2", count: 133},
{id: "444", count: 13},
{id: "433", count: 32},
{id: "3333", count: 2}
],
[
{id: "333", count: 5565},
{id: "2", count: 1633},
{id: "444", count: 136},
{id: "433", count: 362},
{id: "3333", count: 62}
],
[
{id: "333", count: 585},
{id: "2", count: 1383},
{id: "444", count: 138},
{id: "433", count: 328},
{id: "3333", count: 82}
],
]
To this:
const newData = [
{ id: "333", count: [555, 5565, 585] },
{ id: "2", count: [133, 1633, 1383] },
{ id: "444", count: [13, 136, 138] },
{ id: "433", count: [32, 362, 328] },
{ id: "3333", count: [2, 62, 82] }
]
Something I tried was this, but this just gave me an array with each count seperate.
let ob = test.reduce( ( acc, e, i) => {
let obj = {}
e.forEach((value, index) => {
obj[value.recommendationItemIdExternal] = [value.recommendationItemRating];
})
acc.push(obj);
return acc
}, [] );
CodePudding user response：
A nested for loop will do it. Just iterate through the data and store the count (or b) value in another object, using the id as the key.
let adjusted = {};
data.forEach(e => {
for (let item of e) {
if (adjusted[item.id] == undefined)
adjusted[item.id] = [];
if(item.count != undefined)
adjusted[item.id].push(item.count);
else if(item.b != undefined)
adjusted[item.id].push(item.b);
}
});
console.log(adjusted);
const data = [
[{
id: "333",
count: 555
},
{
id: "2",
count: 133
},
{
id: "444",
count: 13
},
{
id: "433",
count: 32
},
{
id: "3333",
count: 2
},
],
[{
id: "333",
count: 5565
},
{
id: "2",
count: 1633
},
{
id: "444",
count: 136
},
{
id: "433",
count: 362
},
{
id: "3333",
count: 62
},
],
[{
id: "333",
b: 585
},
{
id: "2",
b: 1383
},
{
id: "444",
b: 138
},
{
id: "433",
b: 328
},
{
id: "3333",
b: 82
},
],
]
let adjusted = {};
data.forEach(e => {
for (let item of e) {
if (adjusted[item.id] == undefined)
adjusted[item.id] = [];
if(item.count != undefined)
adjusted[item.id].push(item.count);
else if(item.b != undefined)
adjusted[item.id].push(item.b);
}
});
console.log(adjusted);CodePudding user response：
You can easily achieve this result using Map and reduce
const data = [
[
{ id: "333", count: 555 },
{ id: "2", count: 133 },
{ id: "444", count: 13 },
{ id: "433", count: 32 },
{ id: "3333", count: 2 },
],
[
{ id: "333", count: 5565 },
{ id: "2", count: 1633 },
{ id: "444", count: 136 },
{ id: "433", count: 362 },
{ id: "3333", count: 62 },
],
[
{ id: "333", count: 585 },
{ id: "2", count: 1383 },
{ id: "444", count: 138 },
{ id: "433", count: 328 },
{ id: "3333", count: 82 },
],
];
const map = new Map(),
newData = [];
const dict = data.flat().reduce((acc, curr) => {
!acc.has(curr.id)
? map.set(curr.id, [curr.count])
: map.get(curr.id).push(curr.count);
return acc;
}, map);
for (let [id, count] of dict) {
newData.push({ id, count });
}
console.log(newData);CodePudding user response：
You can use a combination of .reduce() and .map() array methods as in the demo below.
const newArray = data.reduce((acc, cur) => cur.map((o, i) => ({
id: o.id,
count: [...(acc[i] && acc[i].count || []), o.count]
})), []);
Please note that this only works if each element of the original array has the ids in the same order, otherwise a little more processing is required.
DEMO
const data= [
[
{id: "333", count: 555},
{id: "2", count: 133},
{id: "444", count: 13},
{id: "433", count: 32},
{id: "3333", count: 2}
],
[
{id: "333", count: 5565},
{id: "2", count: 1633},
{id: "444", count: 136},
{id: "433", count: 362},
{id: "3333", count: 62}
],
[
{id: "333", count: 585},
{id: "2", count: 1383},
{id: "444", count: 138},
{id: "433", count: 328},
{id: "3333", count: 82}
],
];
const newArray = data.reduce((acc,cur) => cur.map((o,i) => ({id:o.id,count:[...(acc[i] && acc[i].count || []),o.count]})),[]);
console.log( newArray );