I have a 1d array match and 2d array data . I can search elements one or several like this :
data[data[:,0] == match[0] ]
data[data[:,0] == match[0] & data[:,0] == match[1] ]
but how do you search for all of them :
data[ data[:,0] == match ]
I suppose inside numba function i can use from in1d() !! :
mask = np.zeros(len(ar1), dtype=bool)
for a in ar2:
mask |= (ar1 == a)
return mask
CodePudding user response:
You can use numpy.isin
:
np.isin(data[:, 0], match)
Example:
data = np.array([[1, 4],[5, 2],[2, 4]])
match = np.array([2, 4])
np.isin(data[:,0], match)
# array([False, False, True])
data[np.isin(data[:, 0], match)]
# array([[2, 4]])