How to return contents of a list in a string in one line?-CodePudding

How can I return a string for the following list:

mark_list1 = ["May", 56, 65, 60, 66, 62]
mark_list2 = ["Jess", 81, 86, 85]

Expected output:

May:56-65-60-66-62
Jess:81-86-85

I have tried doing the following but it I'm stuck since it won't work for all cases:

def get_marks(mark_list):
    for x in mark_list:
        string = mark_list[0]   ":"   str(mark_list[1])
        return string

CodePudding user response：

You can use a generator expression or map with join:

def get_marks(mark_list):
    name, *nums = mark_list
    return f"{name}:{'-'.join(map(str, nums))}"

then

>>> get_marks(["May", 56, 65, 60, 66, 62])
'May:56-65-60-66-62'

CodePudding user response：

I have a better idea，I've tried it and I can get what you want

mark_list1 = ["May", 56, 65, 60, 66, 62]
result = mark_list1[0] ":" '-'.join([str(_) for _ in mark_list1[1:]])
print(result)

>>> 'May:56-65-60-66-62'

This is the picture of my demo

CodePudding user response：

Try -

mark_list1 = ["May", 56, 65, 60, 66, 62]
mark_list2 = ["Jess", 81, 86, 85]

def get_marks(lst):
    a = '-'.join([str(i) for i in lst[1:]])
    result = lst[0]   ':'   a
    return result

print(get_marks(mark_list1)) # May:56-65-60-66-62
print(get_marks(mark_list2)) # Jess:81-86-85