Reading user input and displaying the ASCII equivalent-CodePudding

I'm writing a program that asks the user to input a number and displays the ASCII equivalent. It also displays the ASCII numbers of the 5 previous numbers and the five next numbers.

here's my code

#include <stdio.h>
displayASCIITABLE(int input);
int main()
{
   int input;
  printf("enter a number:\n");
 
 
displayASCIITABLE(input);
return 0;
}
displayASCIITABLE(int input)

{
    printf("Number    Character\n");
   for(int i=input-5;i<=input 5;i  )
{

  printf("%d         %c\n",i,i);
}

}

The code works perfectly but some of the numbers ASCII value is not showing here's an example

for example, the ASCII value of 7 8 9 10 as shown in the image above

CodePudding user response：

These numbers are probably escape codes, for example 10 is a newline. These types of characters aren't supposed to be shown but affect things like formatting

CodePudding user response：

Not all character codes in ASCII are printable. Please, read about ASCII on Wikipedia, it will help you.

For instance, only characters from 32 ( , space) to 126 (~, tilde) are printable (i.e.: they are displayable on a terminal or in a text file, etc). There are also whitespace characters like \n, \r, \t, and others, that are considered control characters, but they do have some visual effect in a terminal (or in a text file, etc).

NOTE: the strange symbols you see in your terminal are not part of ASCII (intended as US-ASCII), but they are an extension to ASCII (but their codes are platform-dependent, since they rely on which character encoding your terminal has).

TL;DR: you cannot print any integer as it were a character; some character codes are just not displayable.