def add(t1, t2):
if len(t1) == len(t2):
    for i in range(len(t1)):
        [t1[i] t2[i]]
elif len(t1) != len(t2):
    return None

t1 = [42, 1024, 23]
t2 = [6, 28, 496]
t3 = add(t1, t2)
print(t1)
print(t2)
print(t3)

The problem of elements in the list is too difficult for me. Please give me a little help.

CodePudding user response：

For a list of pairwise sums, you can modify your code as follows:

def add(t1, t2):
    if len(t1) == len(t2):
        result = []
        for i in range(len(t1)):
            result.append(t1[i] t2[i])
        return result
    else:
        return None

Of course, there are utils that make this shorter:

def add(t1, t2):
    if len(t1) == len(t2):
        return [*map(sum, zip(t1, t2))]
    # None returned implicitly

This built-in-ladden code can be interpreted as "map the sum function onto the pairs produced by zip and unpack the resulting sums into a list".

See some documentation:

• sum
• zip
• map
• unpacking with *

CodePudding user response：

Try this by returning from if statement.

def add(t1, t2):
    if len(t1) == len(t2):
        return [(t1[i]   t2[i] ) for i in range(len(t1)) ]
    
    return None

CodePudding user response：

or be short:

def add(t1, t2):
    return [sum(i) for i in zip(t1, t2)] if len(t1) == len(t2) else None

or even shorter:

def add(*x):
    return [*map(sum, zip(*x))] if set(map(len, x)) == 1 else None