I have a simple program like this:
#include <iostream>
#include <string_view>
class C {
public:
void print(std::string_view v) { std::cout << "string_view: " << v << std::endl; }
void print(bool b) { std::cout << "bool: " << b << std::endl; }
};
int main(int argc, char* argv[]) {
C c;
c.print("foo");
}
When I run it, it prints bool: 1
How can I get C to prefer the string_view
implicit conversion instead of the bool
implicit conversion?
CodePudding user response:
You can turn the string_view
overload into a template function, and add a constraint to it so that it has a higher preference than the bool
overload when it receives a type that can be converted to string_view
.
#include <string_view>
class C {
public:
template<class T>
std::enable_if_t<std::is_convertible_v<const T&, std::string_view>>
print(const T& v) { std::cout << "string_view: " << std::string_view(v) << std::endl; }
void print(bool b) { std::cout << "bool: " << b << std::endl; }
};