Returning the inner namespace of a class as dictionary-CodePudding

Imagine we have a class like as below:

class P1(object):
    def __init__(self,value=0,src='admin'):
        self.value=value
        self.src=src

Is it possible to add a method that returns the name inner variables as a dictionary with name as the name and the value as the value like this:

def getDict(self):
    return dictionary(variables)

which returns:

{
  'value':0,
  'src':'admin'
}

PS I know it can be down by hard coding it, I am asking if there is Pythonic way of doing it with one method call.

CodePudding user response：

You're looking for vars example:

return vars(self)

Output:

{'value': 0, 'src': 'admin'}

CodePudding user response：

You can use __dict__:

A dictionary or other mapping object used to store an object’s (writable) attributes.

def getDict(self):
    return self.__dict__

or vars() builtin, which simply returns the __dict__ attribute:

return vars(self)

Warning: Note that this returns a reference to the actual namespace, and any changes you make to the dictionary will be reflected to the instance.

CodePudding user response：

Yes, you can use magic methods. If not create your own method which returns the dict of value and src. Your code:

class P1(object):
    def __init__(self,value=0,src='admin'):
        self.value=value
        self.src=src
    def getdict(self):
        return {"value":self.value,"src":self.src}      #manual return of dict


x=P1(5,"user")      #checking for non default values
print(x.getdict())

x=P1()              #checking for default values
print(x.getdict())