I need to find a regex expression for a number 1 to 9, followed by trailing zeroes, followed by the end number 1 to 9. As like in a minesweeper game for clearing zeroes.

How do I match the part of an array where like i have 10009 or 2003 ? ,1to9 then zeroes, then 1to9? How would I write it?

does this work? updated: how do I ask this regex or another regex? the one i have below or a (trailing zeroes and 1-9)

(^[1-9][0 ][1-9]$) 

CodePudding user response：

[1-9][0] [1-9]

Move the outside of the square brackets. Otherwise, it will match the literal character.

const regex = new RegExp("[1-9][0] [1-9]")

function test(testCase){
  console.log(regex.test(testCase))
}

test("10009")
test("2003")

<iframe name="sif1" sandbox="allow-forms allow-modals allow-scripts" frameborder="0"></iframe>

To make the first digit optional, you can do:

[1-9]?[0] [1-9]

const regex = new RegExp("[1-9]?[0] [1-9]")

function test(testCase){
  console.log(regex.test(testCase))
}

test("0009")
test("2003")

<iframe name="sif2" sandbox="allow-forms allow-modals allow-scripts" frameborder="0"></iframe>

CodePudding user response：

When you say [0 ] then you are saying that select any of either 0 or

you want is quantifier 0 which means 0 one or more times

You can use ^[1-9]0 [1-9]$

const regex = /^[1-9]0 [1-9]$/;

function test(str) {
  return regex.test(str);
}

console.log(test("10009"));
console.log(test("2003"));

<iframe name="sif3" sandbox="allow-forms allow-modals allow-scripts" frameborder="0"></iframe>