Playground:https://mongoplayground.net/p/YUV_fReyGsr I have following query. I need to combine the result 2 by 2. Meaning I need to combine facet "1","2" as a result and facet "3","4" as another result. It's guaranteed that the number of facet will be even. Also, each pair of facet should get at most one record(it might not matter)
db.collection.aggregate([
{
"$facet": {
"1": [
{
$match: {
"ID": "2"
}
}
],
"2": [
{
$match: {
"array.ID": "2"
}
}
],
"3": [
{
$match: {
"array.ID": "4"
}
}
],
"4": [
{
$match: {
"ID": "4"
}
}
]
}
}
])
The expected result will be
[
{
"1": [
{
"ID": "1",
"array": [
{
"ID": "2",
"attribute1": "456"
},
{
"ID": "3",
"attribute1": "567"
}
],
"attr1": "123"
}
],
"2": [
{
"ID": "4",
"array": [
{
"ID": "5",
"attr1": "456"
}
],
"attr1": "123"
}
]
}
]
CodePudding user response:
I was able to figure this out using $concatArrays
operator, along with $project
.
Database
[
{
"ID": "1",
"attr1": "123",
"array": [
{
"ID": "2",
"attribute1": "456"
},
{
"ID": "3",
"attribute1": "567"
}
]
},
{
"ID": "4",
"attr1": "123",
"array": [
{
"ID": "5",
"attr1": "456"
}
]
}
]
Query
db.collection.aggregate([
{
"$facet": {
"1": [
{
$match: {
"ID": "2"
}
}
],
"2": [
{
$match: {
"array.ID": "2"
}
}
],
"3": [
{
$match: {
"array.ID": "4"
}
}
],
"4": [
{
$match: {
"ID": "4"
}
}
]
}
},
{
"$project": {
_id: 0,
"1": {
"$concatArrays": [
"$1",
"$2"
]
},
"2": {
"$concatArrays": [
"$3",
"$4"
]
}
}
}
])
Result
[
{
"1": [
{
"ID": "1",
"_id": ObjectId("5a934e000102030405000000"),
"array": [
{
"ID": "2",
"attribute1": "456"
},
{
"ID": "3",
"attribute1": "567"
}
],
"attr1": "123"
}
],
"2": [
{
"ID": "4",
"_id": ObjectId("5a934e000102030405000001"),
"array": [
{
"ID": "5",
"attr1": "456"
}
],
"attr1": "123"
}
]
}
]