Show directory path with only files present in them-CodePudding

This is the folder structure that I have.

Using the find command find . -type d in root folder gives me the following result

Result

./folder1
./folder1/folder2
./folder1/folder2/folder3

However, I want the result to be only ./folder1/folder2/folder3. i.e only print the result if there's a file of type .txt present inside.

Can someone help with this scenario? Hope it makes sense.

CodePudding user response：

You may use this find command that finds all the *.txt files and then it gets unique their parent directory names:

find . -type f -name '*.txt' -exec bash -c '
for f; do
   f="${f#.}"
   printf "%s\0" "$PWD${f%/*}"
done
' _ {}   | awk -v RS='\0' '!seen[$0]  '

We are using printf "%s\0" to address directory names with newlines, spaces and glob characters.
Using gnu-awk to get only unique directory names printed

CodePudding user response：

Using Associative array and Process Substitution.

#!/usr/bin/env bash

declare -A uniq_path

while IFS= read -rd '' files; do
  path_name=${files%/*}
  if ((!uniq_path["$path_name"]  )); then
    printf '%s\n' "$path_name"
  fi
done < <(find . -type f -name '*.txt' -print0)

Check the value of uniq_path

declare -p uniq_path