Input n (a positive integer) numbers and work out their sum, average and sum of the squares of the n-CodePudding

I'm a beginner, this is my current code so far. What I'm confused with is on on how to implement "working out the sum of the squares of the numbers".

#include <stdio.h>

int main()
{
    int i,n,Sum=0,numbers;
    float Average;
    
    printf("\nPlease Enter How many Numbers you want?\n");
    scanf("%d",&n);
    
    printf("\nPlease Enter the Number(s) one by one\n");
    for(i=0;i<n;  i)
    {
        scanf("%d", &numbers);
        Sum = Sum  numbers;
    }
    
    Average = Sum/n;

    printf("\nSum of the %d Numbers = %d",n,Sum);
    printf("\nAverage of the %d Numbers = %.2f",n, Average);
    // printf("\nSum of the Square of %d Numbers = %d",n, );
    
    return 0;
}

CodePudding user response：

This is a solution to your problem : ( Changes are marked with //******** )

#include <stdio.h>

int main()
{
    int i,n,Sum=0,numbers, square = 0;//***********************
    float Average;
    
    printf("\nPlease Enter How many Numbers you want?\n");
    scanf("%d",&n);
    
    printf("\nPlease Enter the Number(s) one by one\n");
    for(i=0;i<n;  i)
    {
        scanf("%d", &numbers);
        Sum = Sum  numbers;
        square = square   (numbers*numbers); //***************
    }
    
    Average = Sum/n;

    printf("\nSum of the %d Numbers = %d",n,Sum);
    printf("\nAverage of the %d Numbers = %.2f",n, Average);
    printf("\nSum of the Square of %d Numbers = %d",n, square);//****************
    
    return 0;
}

Although other methods could be used to solve your question.

CodePudding user response：

Sum of squares of numbers has a mathematical formula:

1^2 2^2.... n^2 = (n(n 1)(2n 1))/6

You can use that to directly get the solution.

CodePudding user response：

For the sum of the squares of the numbers as:

#include<stdio.h>
int main()
   {
    int n, sum=0;

    printf("Enter n value: ");
    scanf("%d", &n);

    for(int i=0; i<=n; i  )
       {
        sum  = (i*i);  
       }

    printf("Sum of squares of %d  numbers = %d", n, sum);
    return 0;
   }

CodePudding user response：

You can create a variable and do exactly as you do with Sum, except you are now adding the squares.

int sumOfSqaure = 0;
// code

for(i = 0; i < n;   i)
{
    scanf("%d", &numbers);
    // a = a   b is equal to a  = b
    sumOfSqaure  = numbers;

    sumOfSqaure  = numbers * numbers; // n * n == n ^ 2
}