Reordering a list in a given order-CodePudding

I want to reorder my list in a given order, For example I have a list of ['a', 'b', 'c', 'd', 'e', 'f', 'g'] this has an index of [0,1,2,3,4,5,6] and lets say the new ordered list would have an order of [3,5,6,1,2,4,0] which would result in ['d','f','g', 'b', 'c', 'e', 'a'].

How would you result in such code?

I thought of using for loop by doing the

 for i in range(Len(list))

and after that I thought go using append or creating a new list? maybe but I'm not sure if I'm approaching this right.

CodePudding user response：

All you need to do is iterate the list of indexes, and use it to access the list of elements, like this:

elems =  ['a', 'b', 'c', 'd', 'e', 'f', 'g']
idx =  [3,5,6,1,2,4,0]

result = [elems[i] for i in idx]
print(result)

Output:

['d', 'f', 'g', 'b', 'c', 'e', 'a']

CodePudding user response：

import numpy as np

my_list =  ['a', 'b', 'c', 'd', 'e', 'f', 'g']

def my_function(my_list, index):
    return np.take(my_list, index)

print(my_function(my_list, [3,5,6,1,2,4,0]))

Output: ['d' 'f' 'g' 'b' 'c' 'e' 'a']