Remove first \n from array-CodePudding

How to remove first RemoveThisX\n from array

['RemoveThis1\nDontRemove\nDontRemove','RemoveThis2\nDontRemove\nDontRemove', 'RemoveThis3\nDontRemove\nDontRemove', 'RemoveThis4\nDontRemove\nDontRemove']

Trying to remove RemoveThis1\n, RemoveThis2\n, RemoveThis3, RemoveThis4\n

Final result need to be

['DontRemove\nDontRemove','DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove']

CodePudding user response：

a_list = ['RemoveThis1\nDontRemove\nDontRemove','RemoveThis2\nDontRemove\nDontRemove', 'RemoveThis3\nDontRemove\nDontRemove', 'RemoveThis4\nDontRemove\nDontRemove']

result = [item[item.find('\n') 1:] for item in a_list]
print(result)

['DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove']

CodePudding user response：

test_list = ['RemoveThis1\nDontRemove\nDontRemove','RemoveThis2\nDontRemove\nDontRemove', 'RemoveThis3\nDontRemove\nDontRemove', 'RemoveThis4\nDontRemove\nDontRemove']
result = ["\n".join(item.split("\n")[1:]) for item in test_list]
print(result)

Output will be:

['DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove', 'DontRemove\nDontRemove']

CodePudding user response：

assuming:

initial_list = ['RemoveThis1\nDontRemove\nDontRemove','RemoveThis2\nDontRemove\nDontRemove', 'RemoveThis3\nDontRemove\nDontRemove', 'RemoveThis4\nDontRemove\nDontRemove']

I would recommend using either the map function:

mapped_list = list(map(lambda x: x[x.find('\n')   1:], initial_list))

or list comprehension:

comprehended_list = [string[string.find('\n')   1:] for string in initial_list]

Both should produce the asked list.