My async fetch function is embedded on names.php and when I activate the function it takes me to the endpoint it POSTS to: change-name.php. I want to remain on the names.php page but refresh that page after the fetch function has run.
I am clicking the span below to open a text field where I add a name and click the button:
<span onclick="addGuestName(this)">
<button class="addPaxName btn btn-xs btn-warning">ADD</button>
This works perfectly fine. And updates the name but I am transported to the /change-name.php page after clicking the ADD button.
My desired response is to remain on the original page with a page refresh after the fetch function has completed. How do I get this result.
async function updateGuestName(paxid,name){
paxIDbody = '{"pxid": "' paxid '", "name": "' name '"}';
console.log("PaxID:", paxIDbody);
try {
const settings = {
method: "POST",
headers: {
"Content-type": "application/json; charset=UTF-8"
},
body: paxIDbody,
};
const response = await fetch(
"/change-name.php",
settings
);
const data = await response.json();
console.log("DATA: ",data);
} catch (error) {
console.log("ERROR: ",error);
}
}
function addGuestName(obj) {
const itemClicked = obj;
const paxid = obj.id;
const addPaxName = itemClicked.nextElementSibling;
const addPaxNameButton = itemClicked.nextElementSibling;
addPaxNameButton.style.display = 'inline-block';
var addPaxNameField = document.createElement('input');
addPaxNameField.setAttribute('type', 'text');
addPaxNameField.setAttribute('name', 'visitorNameSurname[]');
addPaxNameField.setAttribute('placeholder', 'Enter Name & Surname');
itemClicked.parentNode.insertBefore(addPaxNameField, itemClicked.nextSibling);
addPaxNameField.setAttribute("required", "required");
addPaxNameButton.addEventListener('click', () => {
const name = addPaxNameField.value;
updateGuestName(paxid,name);
})
}
My PHP endpoint returns JSON after the DB update:
header('Content-type:application/json;charset=utf-8');
$myObj=new \stdClass();
$myObj->status = $status;
$myObj->message = $message;
$myJSON = json_encode($myObj);
echo $myJSON;
CodePudding user response:
Default button type is submit. Use onsubmit with event.preventDefault()
inside onsubmit
callback. If you don't need browser's form validation, you can use more straightforward type="button"
. For refreshing page look at location.reload().
CodePudding user response:
addPaxNameButton.addEventListener('click', (e) => {
e.preventDefault();
const name = addPaxNameField.value;
updateGuestName(paxid,name);
})