The client I am using returns json like this:
[
{
"source": "ANY"
}
]
That is, the element of the array that the object is in.
I'm trying to make a request like this:
restTemplate.postForObject<AbcdResponse>(
"/address",
listOf(value).let { JsonHttpEntity(it) }
)
data class AbcdResponse(
val obj: AbcdObject
)
data class DaDataAddress(
val source: String?
)
But I get the HttpMessageNotReadableException
exception:
org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize instance of `com.app.client.abcd.domain.AbcdResponse` out of START_ARRAY token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `com.app.client.abcd.domain.AbcdResponse` out of START_ARRAY token
at [Source: (ByteArrayInputStream); line: 1, column: 1]
How can I deserialize the response correctly?
CodePudding user response:
As you probably noticed, the response as a whole is a JSON array. You can tell by the square brackets [ ... ]
surrounding the whole thing.
Because of this, you cannot deserialize it as an object (such as AbcdResponse
). What you should do instead is use List<DaDataAddress>
instead of AbcdResponse
.
CodePudding user response:
You don't really need AbcdResponse
. What you need is to use a ParameterizedTypeReference
as follows while calling the service:
restTemplate.exchange("/address",
HttpMethod.POST,
listOf(value).let { JsonHttpEntity(it) },
ParameterizedTypeReference<List<DaDataAddress>>() {})
The reason is that the service that you are calling is returning a JSON array of JSON objects.