PHP date format variable-CodePudding

I would like to change the date format in the following code:

#search for all event start dates
$starts = $sxml->xpath('//event/startdate');

#get the unique start dates of these event
$dates = array_unique($starts);

foreach($dates as $date) {     
   echo "<li class='header'><h1>{$date}</h1></li>" ."\n";

currently, it pulls from an XML feed as 25/11/2021 and I would like to show it as Thursday 25 November 2021 - probably as multiple variables. However, date() is not working.

Any help is appreciated!

CodePudding user response：

Using the DateTime object it can be easy and accurate

$dates = ['25/11/2021','24/11/2021','23/11/2021'];

foreach ( $dates as $date){
    $df = (DateTime::CreateFromFormat('d/m/Y', $date))->format('l d F Y');
    echo "<li class='header'><h1>{$df}</h1></li>" ."\n";
}

RESULTS

<li class='header'><h1>Thursday 25 November 2021</h1></li>
<li class='header'><h1>Wednesday 24 November 2021</h1></li>
<li class='header'><h1>Tuesday 23 November 2021</h1></li>

PHP Manual for DateTime object

CodePudding user response：

use date_format

date_format(DateTimeInterface $object, string $format): string

Note:

According to doc : date_format() is not supported for dd/mm/YY date format

l: Sunday through Saturday

j: Day of the month(1 to 31)

F: January through December

Y: 4-digits years

$dates = ['2021/2/11','2021/12/12'];

foreach($dates as $date) {     
    $d = date_format(date_create($date),'l j F Y');
    echo "<li class='header'><h1>${d}</h1></li>" ."\n";
}

OUTPUT

<li class='header'><h1>Thursday 11 February 2021</h1></li>
<li class='header'><h1>Sunday 12 December 2021</h1></li>