Django slug with id in url-CodePudding

How can made a url with slug and id, like:

https://example.com/product/beauty-slug/1

The Product model can accept repeated title product, and insted use unique slug i prefer use the slug with id

models.py

class Product(models.Model):
    user = models.ForeignKey(User, on_delete=models.CASCADE)
    product_title = models.CharField(max_length=255, default='product_title')    
    slug = models.SlugField(max_length=250,unique=True,null=True)

    def __str__(self):
        return self.product_title
    
    def get_absolute_url(self):
        return reverse('product_change', kwargs={'slug': self.slug})

    def save(self, *args, **kwargs): 
        if not self.slug:
            self.slug = slugify(self.product_title)
            return super().save(*args, **kwargs)

And how use it in a template

product_list.html

<a href="{% url 'product_view' product.slug %}">see product</a>

urls.py

...
path('product/<slug:slug>', ProductView.as_view(), name='product_view'),
...

Thats works, but i know i gona have identical products title, so i think with id is better to my case, becouse if needed costumer can reference the order to seller with id number...

CodePudding user response：

As path you can use:

path('product/<slug:slug>/<int:pk>/', ProductView.as_view(), name='product_view'),

You thus can link to the URL with:

<a href="{% url 'product_view' product.slug product.pk %}">see product</a>

If you update the product_change URL pattern as well, the .get_absolute_url() method [Django-doc] of the model should be rewritten to:

class Product(models.Model):
    # …
    
    def get_absolute_url(self):
        return reverse('product_change', kwargs={'slug': self.slug, 'pk': self.pk})