I have an input data like this:
('Volvo', [23880.0, 10200.0])
('SsangYong', [11400.0])
('Fiat', [7800.0])
I would like to identify the counts for each key.
I have tried multiple ways as below but it did not work.
for k, v in kvdata.items():
(k, count) = (k, count(v))
return [(k, count)]
The desired output should be:
('Volve', 2)
('SsangYong', 1)
('Fiat', 1)
CodePudding user response:
Hey I got the point.
t = (('Volvo', [23880.0, 10200.0]),
('SsangYong', [11400.0]),
('Fiat', [7800.0]))
for (k,v) in t:
print(k,len(v))
Output is:
Volvo 2
SsangYong 1
Fiat 1
CodePudding user response:
The solution to your question is to wrap all cars inside a variable and modify your problematic for loop.
You have to enclose all the cars inside a variable like this:
car brand = (('Volvo', [23880.0, 10200.0]), ('SsangYong', [11400.0]), ('Fiat', [7800.0]))
Next you need to change something in your cycle. You can simplify it like this:
for (k,v) in car brand:
print(k,len(v))
The output will be like yours, but without round brackets, commas, and quotes
COMPLETE SOLUTION CODE
car brand = (('Volvo', [23880.0, 10200.0]), ('SsangYong', [11400.0]), ('Fiat', [7800.0]))
for (k,v) in car brand:
print(k,len(v))