reverse index from string-CodePudding

For the input text: I would like to receive following solution: rafal

"r" 0 -5

"a" 1 -4

"f" 2 -3

"a" 3 -2

"l" 4 -1

where first column are letters given in text, second column are indexes values and third column are reverse indexes values.

I performed enumeration: for idx, znak in enumerate(tekst): print('"' znak '"', idx)

which gave me following output: daj tekst: rafal "r" 0

"a" 1

"f" 2

"a" 3

"l" 4

I do not know how to print reverse index values. When i created new string which was reversion of original text and enumerate through this:

for idx, znak in enumerate(tekst): new_txt = tekst[::-1] for r_idx, znak in enumerate(tekst): print('"' znak '"', idx, r_idx)

I receievd following output:

daj tekst: rafal "r" 0 0

"a" 0 1

"f" 0 2

"a" 0 3

"l" 0 4

"r" 1 0

"a" 1 1

"f" 1 2

"a" 1 3

"l" 1 4

"r" 2 0

"a" 2 1

"f" 2 2

"a" 2 3

"l" 2 4

"r" 3 0

"a" 3 1

"f" 3 2

"a" 3 3

"l" 3 4

"r" 4 0

"a" 4 1

"f" 4 2

"a" 4 3

"l" 4 4

How can I receive desired output ?

CodePudding user response：

You can try code below:

def getStringData(string):
  array = list(string)
  length = len(array)
  for index, value in enumerate(array):
    print("'" value "'", index, index-length)
getStringData("rafal")

Output

'r' 0 -5
'a' 1 -4
'f' 2 -3
'a' 3 -2
'l' 4 -1

CodePudding user response：

word = "rafal"

for i in range(len(word)): 
    print(f"{word[i]}\t{i}\t{i-len(word)}")

CodePudding user response：

You could use two levels of enumerate, with one of them starting at the first negative index:

s = 'rafal'
for n,(i,c) in enumerate(enumerate(s),-len(s)):
    print(repr(c),i,n)

'r' 0 -5
'a' 1 -4
'f' 2 -3
'a' 3 -2
'l' 4 -1