Random choice without repeats-CodePudding

I need to generate a unique element each time random choice is run without any repeats each time its run (lists are not allowed to be used ) eg : (x,y,z) (y,x,z) (z,y,x)

from random import choice operator=random.choice("xyz")

CodePudding user response：

Is this what you are looking for:

import random

for i in range(5):
    print(random.sample("xyz", 3))

['y', 'z', 'x']
['z', 'y', 'x']
['z', 'x', 'y']
['x', 'y', 'z']
['z', 'x', 'y']

I think this is an equivalent solution:

for i in range(5):
    x = list("xyz")
    random.shuffle(x)
    print(x)

CodePudding user response：

According to your example, you're trying to do permutations to find unique elements?

from itertools import permutations

for i in permutations("xyz"):
    print (i)

('x', 'y', 'z')
('x', 'z', 'y')
('y', 'x', 'z')
('y', 'z', 'x')
('z', 'x', 'y')
('z', 'y', 'x')