Extract files and rename specific file with specific extension using 7zip?-CodePudding

I would like to use 7ZIP to extract files with specific extensions only, and then rename one of them accordingly.

Also, i must do this using a batch script (.bat) - No powershell or other methods.

I currently set up the following script, on a bat file:

@echo off
REM Force UTF-8 to fix some output problems
chcp 65001 > nul

REM Six columns, space delimited
for /f "tokens=6 delims= " %%A in ('"C:\Tools\7za.exe" l VPN.zip -ba -r *\*.ovpn') do (
    "C:\Tools\7za.exe" e VPN.zip -ba -r %%A > Test.ovpn
)

PAUSE

Output:

It exracts two files.

One is the archive itself (Archive...ovpn) The second one is the one i renamed (Test.ovpn) The second archive, instead of being the actual renamed archive, contains 7Zip logs... Log is below.

Processing archive: VPN.zip

Extracting  folder_name\Original_archive.ovpn

Everything is Ok

Size:       411 Compressed: 5800

It lists the files in my zipped archive...

What i want to achieve is:

Extract files only to a folder called "VPN", and not folder_name.

If the files contains the extension .ovpn, rename that file to "Test.ovpn"

I am very sorry if this question seems silly. I am quite new on batch scripting field and here is the only place where i can get some help...

Thank you for anyone that helps me.

Edit: I updated the questions with the codes i'm using, since on comments they said this question was'nt clear enough...

CodePudding user response：

I solved it by using the following code:

REM Extract files in archive
for %%f in (VPN.zip) do (

"C:\Tools\7za.exe" e "%%f" -ba -y -so -r *\*.ovpn 1>C:\VPN\VPN.ovpn 2>nul
"C:\Tools\7za.exe" e "%%f" -ba -y -r *\*.p12 -oC:\VPN >nul
"C:\Tools\7za.exe" e "%%f" -ba -y -r *\*.key -oC:\VPN >nul

) >nul