I have a list with alphanumeric characters like as shown below
l1 = ['G1','L1']
I would like to know whether we have something like below
for i in range(l1): #this doesn't work because range is only for numeric values
for i in range(G1:L1): #this also doesn't work
However, I want the i
value at each run to change from G1
to H1
to I1
to J1
to K1
to L1
CodePudding user response:
Range always expects a number and cannot work with strings.
However, you can use the built-in ord()
function to convert letters to numbers and then use the chr()
function to convert them back from numbers to ASCII characters.
Code
a = [chr(c) '1' for c in range(ord('G'), ord('M'))]
print(a)
Output
['G1', 'H1', 'I1', 'J1', 'K1', 'L1']
Update: Solution for double characters.
Doing it for double characters is a little more complicated, but this StackOverflow answer has a solution to that. You can simply use the from_excel()
and to_excel()
functions from that answer and replace them in my above code as follows.
Code
a = [to_excel(i) for i in range(from_excel('G'), from_excel('AG'))]
print(a)
Output
['G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z', 'AA', 'AB', 'AC', 'AD', 'AE', 'AF']
CodePudding user response:
You can use:
from openpyxl.utils import coordinate_to_tuple, get_column_letter
def excel_range(start, end):
t1 = coordinate_to_tuple(start)
t2 = coordinate_to_tuple(end)
rows, cols = zip(t1, t2)
cells = []
for r in range(rows[0], rows[1] 1):
for c in range(cols[0], cols[1] 1):
cells.append(f'{get_column_letter(c)}{r}')
return cells
cells = excel_range('AA1', 'AC4')
Output:
>>> cells
['AA1',
'AB1',
'AC1',
'AA2',
'AB2',
'AC2',
'AA3',
'AB3',
'AC3',
'AA4',
'AB4',
'AC4']