How do replace # with occurrence of number using regular expression in java-CodePudding

I am having two string objects

 String uri= employee/details[0].address[1].telephone

 String uriPath=/employee/details/#/address/#/phone

And i need to update uriPath to /employee/details/0/address/1/phone . i need to go along uri and get the numbers within [] and replace # inside uriPath in order.

CodePudding user response：

Why not just replace the '[', ']' and '.' with a '/'?

String uriPath = "/" uri.replace('[','/').replace(']','/').replace('.','/')

CodePudding user response：

Using String#replaceAll:

String uri = "employee/details[0].address[1].telephone";
uri = uri.replaceAll("\\[(\\d )\\]\\.", "/$1/");
System.out.println(uri);  // employee/details/0/address/1/telephone

CodePudding user response：

It sounds like you need to parse one string and replace the other.

Scanner scan = new Scanner(uri);

while( scan.hasNextInt() ){
    int a = scan.nextInt();
    uriPath = uriPath.replaceFirst(Pattern.quote("#"), a);
}

I used a Scanner to grab the ints, but you could use a pattern matcher.

Pattern p = Pattern.compile( "\\[(\\d )\\]" );

Then do a loop.

Matcher m = p.matcher( uri );
while(m.find()){
    uriPath = uriPath.replaceFirst(Pattern.quote("#"), m.group(1));
}

That will look for [0] and grab the zero and replace # s sequentially.