I have a class-based view (lets say, DetailView) which renders a page with a list of objects based on slug in the URL. But if an object with the given slug does not exist, it gives me an error. What I want is to redirect to the main page instead of raising an error. It should be easy, but I can't understand how to do this, so I wanna ask for help here.
Simply, I wanna find something like "success_url" but for errors.
Example:
views.py
class ShowExerciseRecords(ListView):
def get_queryset(self):
exercise = Exercise.objects.get(slug=self.kwargs['slug'])
return exercise.record__set.all()
urls.py
urlpatterns = [
path('/exercise/<slug:slug>/', ShowExerciseRecords.as_view())
path('', index, name='home')
]
CodePudding user response:
please try this code,
class ShowExerciseRecords(ListView):
def get_queryset(self):
records = Record.objects.none() # you should replace the exact model name
exercise = Exercise.objects.filter(slug=self.kwargs['slug']).first()
if exercise:
records = exercise.record__set.all()
return records
def get(self, request, *args, **kwargs):
self.object_list = self.get_queryset()
if self.object_list:
context = self.get_context_data()
return self.render_to_response(context)
return redirect("main-page-url") # you should change the url to your case
CodePudding user response:
you can use try except for example:
try:
Exercise.objects.get(slug=self.kwargs['slug'])
except Exercise.DoesNotExist:
redirect("main-page-url")