Break inside a function with for-CodePudding

(Python 3.10.4)

I have a for condition and inside this for a have a function that need a break and go back to the top like "continue" do, but i can't use break outside a loop, how can i go back to the top of the code? I will use this function so many times after and i don't want to have so many if in my code

import time

def function1():

 if pyautogui.locateCenterOnScreen('file.png')

 pyautogui.moveTo(x=612, y263)
 time.sleep(1)
 break

How can i break the code in this case:

for c in range (0,10):
print('begin for')

#FUNCTION
function1():
#
#
#REST OF THE CODE

CodePudding user response：

It's hard to imagine what you meant by 'break the code' with your incorrect code indentations. I guess you meant to break the for loop when the function breakes.

Use a variable out side the function to indicate when you're done with your function.

And check for the value of the variable within the for loop to break or pass

br = 0
def function1():

    if pyautogui.locateCenterOnScreen('file.png')
        pyautogui.moveTo(x=612, y=263)
        br = 1 
        time.sleep(1)
        return 0



for c in range (0,10):
    print('begin for')  
    #FUNCTION
    function1()

    if br == 1:
        break
    else:
        pass
    
#
#
#REST OF THE CODE

CodePudding user response：

If you want to jump out of a function, use return please.
For example

def test():
    for i in range(10):
        print(i)
        if i == 5:
            return i

Output