Problem when calling dictionary variables. TypeError: tuple indices must be integers or slices, not-CodePudding

I would like to print variable_1 of result1 and variable_3 of result2. I would like to try and continue to use similar syntax where I can specify the call of result1 and variable_1. I want to print and recall both conditions.

I get the following error: TypeError: tuple indices must be integers or slices, not str

How can I solve?

def a():
    result1 = {}  
    if 2 > 1:
        print("yes 1")
        result1['variable_1'] = 2 2
        result1['variable_11'] = 'yes11'
                  
    else:
        print("no 1")
        result1['variable_2'] = 'no1'



    result2 = {}            
    if 3 < 2:
        print("yes 2")
        result2['variable_3'] = 'yes2'
    else:
        print("no 2")
        result2['variable_4'] = 'no2'
        
    return result1, result2

result1 = a()
result2 = a()

print(result1['variable_1'])
print(result2['variable_3'])

CodePudding user response：

Your code as given has a() returns two values.

so what your code does is the following:

result1 = (result1, result2)
result2 = (result1, result2)

where the values within the parenthesis are variables based on the variables within a().

What you can do:

def a():
    result1 = {}  
    if 2 > 1:
        print("yes 1")
        result1['variable_1'] = 2 2
        result1['variable_11'] = 'yes11'
                  
    else:
        print("no 1")
        result1['variable_2'] = 'no1'



    result2 = {}            
    if 3 < 2:
        print("yes 2")
        result2['variable_3'] = 'yes2'
    else:
        print("no 2")
        result2['variable_4'] = 'no2'
        
    return result1, result2

result1, result2 = a()

print(result1['variable_1'])
print(result2['variable_3'])

A better way to lessen the confusion:

def a():
    r1 = {"variable_1": None,
          "variable_11": None,
          "variable_2": None}  
    if 2 > 1:
        print("yes 1")
        r1['variable_1'] = 2 2
        r1['variable_11'] = 'yes11'
    else:
        print("no 1")
        r1['variable_2'] = 'no1'

    r2 = {"variable_3": None,
          "variable_4": None}            
    if 3 < 2:
        print("yes 2")
        r2['variable_3'] = 'yes2'
    else:
        print("no 2")
        r2['variable_4'] = 'no2'
        
    return r1, r2

result1, result2 = a()

print(result1['variable_1'])
print(result2['variable_3'])

The problem also stems from the fact that you don't have default values for variable_3 since in result2, 3 < 2 is False, so r2['variable_4'] is defined but r2['variable_3'] isn't.

I set the default values to None; but you can set it to anything you wish.

That said, while the above code works, I'm not entirely sure what you're trying to do.

CodePudding user response：

You are assigning two different variables both to the same thing: a tuple. What you really want is tuple unpacking. So instead of doing:

result1 = a()
result2 = a()

Do:

result1, result2 = a()

You do this because a() returns 2 different values, and you want to assign a var to each one. It’s equivalent to doing

result1 = a()[0]
result2 = a()[1]