Python: a list with an Element with "|", (and) operator-CodePudding

I have a function that analyse the transfer-text(buchungstext) of a bank transfer. Python looks if a word is contained in the transfer-text(buchungstext) then returns a GUID, the GUID is then the target booking account. But now I would like if in the list not only one word is searched, but two words are required with an AND-operation. It is important that the words can also be twisted in the sentence.

I've tried it like this before: 'LINEA'|'MADRID'

buchungstext = "METRO MADRID LINEA 7 MASTERCARD - MADRID " 


    # Tickets und Transport
    elif any(wort.upper() in buchungstext.upper() for wort in [  'LINEA'|'MADRID'   ,'METRO BARCELONA','METRO DE MADRID','LUFTHANSA','Trainline','SNCF TGV.COM','LIM*FAHRTKOSTEN','DB Reisezentrum','FINNAIR','DB Vertrieb GmbH','BOLT.EU','OEBB', 'DB BAHN A-NR','UBER','Flixbus','TIER','MVG RAD']):
        GUIDzwei = "d45xxxxxxxxxxxxxx013ab953ef26af2"
        return()



    # Hotels
    elif any(wort.upper() in buchungstext.upper() for wort in ['Hotel']):
        GUIDzwei = "d45xxxxxxxxxxxxxx013ab953ef26af2"
        return()

    # Mailservices, Post, DHL
    elif any(wort.upper() in buchungstext.upper() for wort in ['bpost','Deutsche Post','UPS','DHL']):
        GUIDzwei = "d45xxxxxxxxxxxxxx013ab953ef26af2"
        return()

# etc....

CodePudding user response：

If I understand the problem correctly, this may help.

You have a string (buchungstext) comprised of a number of whitespace delimited words.

You want to find out if all of a set of words exist in that string.

The search is not case sensitive.

Therefore:

buchungstext = "METRO MADRID LINEA 7 MASTERCARD - MADRID"

def check(sentence, words):
    # tokenise and convert to lowercase
    los = {w.lower() for w in sentence.split()}
    return all(k.lower() in los for k in words)

print(check(buchungstext, ['mastercard', 'metro']))
print(check(buchungstext, ['mastercard', 'munich']))

Output:

True
False

This gives a logical AND for the list passed as the second parameter. If you want logical OR just change all to any

CodePudding user response：

You can just change in to re.search. Main question is how to search for existence of all provided words in any order. We can do that with regex lookahead

r"(?=.*WORD1)(?=.*WORD2)"

So your crucial part could look like that:

any(re.search(wort, buchungstext, re.I | re.X | re.DOTALL) for wort in [r"(?=.*LINEA)(?=.*MADRIT)", "LUFTHANSA", "..."])

X flag tells the match is when we find both, not any of word in A|B.

I flag is for ignore case search

DOTALL flag makes .* match newline as well

CodePudding user response：

Can't you just use for wort in [ 'LINEA', 'MADRID' ,'METRO BARCELONA', ...] as long as, when you're looking for words inside the list, the or operations is implied?