Hy have a string which corresponds to a file location in linux, i want to extract just the part of it that corresponds to the username and that always comes after the 6th forward slash and then store it in a new string variable:
str1 = "/usr/share/nginx/website/orders/jim/17jkyu.xlsx"
n = 0
user = ','
for ch in str1:
if ch == '/':
n = 1
if n == 6:
user.join(ch)
if n == 7:
break
print(user '\n')
In this case i want to extract jim and put it into the string user. So far is not working
CodePudding user response:
You can use the split
Python built-in function over the /
symbol, and select the 7th element:
str1.split('/')[6]
CodePudding user response:
Split the string then pull the index value.
str1 = "/usr/share/nginx/website/orders/jim/17jkyu.xlsx"
user = str1.split('/')[6]
CodePudding user response:
You can check if n=6 and the current char is not /
, set user to an empty string and concat the character.
str1 = "/usr/share/nginx/website/orders/jim/17jkyu.xlsx"
n = 0
user = ''
for ch in str1:
if ch == '/':
n = 1
if n == 7:
break
if n == 6 and ch != '/':
user = ch
print(user)
Output
jim