I have example data as follows:
dat <- structure(list(
zipcode = c(1001, 1002, 1003, 1004, 1101, 1102, 1103, 1104, 1201, 1202, 1203, 1302),
areacode = c(4, 4, NA, 4, 4, 4, NA, 1, 4, 4, NA, 4),
type = structure(c(1L, 1L, NA, 1L, 2L, 2L, NA, 1L, 1L, 1L, NA, 1L),
.Label = c("clay", "sand"), class = "factor"),
region = c(3, 3, NA, 3, 3, 3, NA, 3, 3, 3, NA, 3),
do_not_fill = c(1, NA, NA, 1, 1, NA, NA, 1, NA, NA, NA, 1)),
class = c("data.table", "data.frame"), row.names = c(NA, -4L))
zipcode areacode type region do_not_fill
1: 1001 4 clay 3 1
2: 1002 4 clay 3 NA
3: 1003 NA <NA> NA NA
4: 1004 4 clay 3 1
5: 1101 4 sand 3 1
6: 1102 4 sand 3 NA
7: 1103 NA <NA> NA NA
8: 1104 1 clay 3 1
9: 1201 4 clay 3 NA
10: 1202 4 clay 3 NA
11: 1203 NA <NA> NA NA
12: 1302 4 clay 3 1
I want to fill ONLY the columns areacode, type and region based on two conditions.
- The
areacodehas to be the same before and after theNA. - The first two digits of the
zipcodehave to be the same before and after the NA.
Based on this solution, and this solution, I attempted following (however data.table solutions are welcomed and even preferred):
library(dplyr)
dat |>
mutate(type = as.character(type)) |>
mutate(across(1:4,
~ ifelse(is.na(.) & lag(areacode) == lead(areacode) &
lag(as.numeric(substr(zipcode, 1, 2))) == lead(as.numeric(substr(zipcode, 1, 2))),
lag(.),
.)))
But somewhere I am doing something wrong, because I get:
Error:
! `n` and `row.names` must be consistent.
Run `rlang::last_error()` to see where the error occurred.
Desired output:
zipcode areacode type region do_not_fill
1: 1001 4 clay 3 1
2: 1002 4 clay 3 NA
3: 1003 4 clay 3 NA
4: 1004 4 clay 3 1
5: 1101 4 sand 3 1
6: 1102 4 sand 3 NA
7: 1103 NA <NA> NA NA
8: 1104 1 clay 3 1
9: 1201 4 clay 3 NA
10: 1202 4 clay 3 NA
11: 1203 NA <NA> NA NA
12: 1302 4 clay 3 1
EDIT
as_tibble(dat) |>
mutate(type = as.character(areacode)) |>
mutate(across(1:4,
~ ifelse(is.na(.) & lag(areacode) == lead(areacode) &
lag(as.numeric(substr(zipcode, 1, 2))) == lead(as.numeric(substr(zipcode, 1, 2))),
lag(.),
.)))
# A tibble: 12 x 5
zipcode areacode type region do_not_fill
<dbl> <dbl> <chr> <dbl> <dbl>
1 1001 4 4 3 1
2 1002 4 4 3 NA
3 1003 4 4 3 NA
4 1004 4 4 3 1
5 1101 4 4 3 1
6 1102 4 4 3 NA
7 1103 NA NA NA NA
8 1104 1 1 3 1
9 1201 4 4 3 NA
10 1202 4 4 3 NA
11 1203 NA NA NA NA
12 1302 4 4 3 1
CodePudding user response：
You need to convert it to a tibble first. I think this is because data.table has extra attributes
Have a look at the rownames,
rownames(as_tibble(dat))
[1] "1" "2" "3" "4" "5" "6" "7" "8" "9" "10" "11" "12"
rownames(dat)
[1] "1" "2" "3" "4"
as_tibble(dat) |>
mutate(type = as.character(type)) |>
mutate(across(1:4,
~ ifelse(is.na(.) & lag(areacode) == lead(areacode) &
lag(as.numeric(substr(zipcode, 1, 2))) == lead(as.numeric(substr(zipcode, 1, 2))),
lag(.),
.)))
# A tibble: 12 x 5
zipcode areacode type region do_not_fill
<dbl> <dbl> <chr> <dbl> <dbl>
1 1001 4 clay 3 1
2 1002 4 clay 3 NA
3 1003 4 clay 3 NA
4 1004 4 clay 3 1
5 1101 4 sand 3 1
6 1102 4 sand 3 NA
7 1103 NA NA NA NA
8 1104 1 clay 3 1
9 1201 4 clay 3 NA
10 1202 4 clay 3 NA
11 1203 NA NA NA NA
12 1302 4 clay 3 1