is it possible to make the typescript map part of the object attributes-CodePudding

I am defined the MenuItem like this to parse the server side rest api response:

  type MenuItem = {
    id: number;
    name: string;
    path: string;
    tree_id_path: string;
    children: MenuItem[];
  };

the server side return more than 4 fields, but I only want the MenuItem to take 4 fields. what should I do to make it work like this? Now I am using as to cast the reponse to MenuItem list.

  export async function roleMenuTree(options?: { [key: string]: any }) {
    let response = await request<API.ApiResponse>('/manage/permission/role/v1/role/menu', {
      method: 'POST',
      body: JSON.stringify({}),
      ...(options || {}),
    });
    let dataList = response.result as API.MenuItem[];
    return dataList;
  }

CodePudding user response：

You can easily achieve this using es6.

By using the Spread syntax

let { unWantedFields ,...rest} = response.result;
let result = rest

Or you can use Destructuring assignment to include your desire props

let {id, name, path} = response.result;
let result = {id, name, path}

CodePudding user response：

As an alternative you can return a new object

export async function roleMenuTree(options?: { [key: string]: any }) {
    let response = await request<API.ApiResponse>('/manage/permission/role/v1/role/menu', {
      method: 'POST',
      body: JSON.stringify({}),
      ...(options || {}),
    });
    let newResult: MenuItem = {
      id: response?.result?.id,
      name: response?.result?.name,
      path: response?.result?.path,
      tree_id_path: response?.result?.tree_id_path,
      children: //Here your MenuItem[]
    }
    let dataList = newResult;
    return dataList;
  }

Or you can use this approach (If you have same names in api response as well)

   let {id, name, path, tree_id_path, children} = response.result;